4x^2+110x-200=0

Solution for 4x^2+110x-200=0 equation:

4x^2+110x-200=0

a = 4; b = 110; c = -200;
Δ = b2-4ac
Δ = 1102-4·4·(-200)
Δ = 15300
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{15300}=\sqrt{900*17}=\sqrt{900}*\sqrt{17}=30\sqrt{17}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(110)-30\sqrt{17}}{2*4}=\frac{-110-30\sqrt{17}}{8}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(110)+30\sqrt{17}}{2*4}=\frac{-110+30\sqrt{17}}{8}
$